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\frac{2\sqrt{2}\sqrt{\frac{1}{36}}}{\sqrt{\frac{4\times 2+1}{2}}}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{2\sqrt{2}\times \frac{1}{6}}{\sqrt{\frac{4\times 2+1}{2}}}
Rewrite the square root of the division \frac{1}{36} as the division of square roots \frac{\sqrt{1}}{\sqrt{36}}. Take the square root of both numerator and denominator.
\frac{\frac{2}{6}\sqrt{2}}{\sqrt{\frac{4\times 2+1}{2}}}
Multiply 2 and \frac{1}{6} to get \frac{2}{6}.
\frac{\frac{1}{3}\sqrt{2}}{\sqrt{\frac{4\times 2+1}{2}}}
Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.
\frac{\frac{1}{3}\sqrt{2}}{\sqrt{\frac{8+1}{2}}}
Multiply 4 and 2 to get 8.
\frac{\frac{1}{3}\sqrt{2}}{\sqrt{\frac{9}{2}}}
Add 8 and 1 to get 9.
\frac{\frac{1}{3}\sqrt{2}}{\frac{\sqrt{9}}{\sqrt{2}}}
Rewrite the square root of the division \sqrt{\frac{9}{2}} as the division of square roots \frac{\sqrt{9}}{\sqrt{2}}.
\frac{\frac{1}{3}\sqrt{2}}{\frac{3}{\sqrt{2}}}
Calculate the square root of 9 and get 3.
\frac{\frac{1}{3}\sqrt{2}}{\frac{3\sqrt{2}}{\left(\sqrt{2}\right)^{2}}}
Rationalize the denominator of \frac{3}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{\frac{1}{3}\sqrt{2}}{\frac{3\sqrt{2}}{2}}
The square of \sqrt{2} is 2.
\frac{\frac{1}{3}\sqrt{2}\times 2}{3\sqrt{2}}
Divide \frac{1}{3}\sqrt{2} by \frac{3\sqrt{2}}{2} by multiplying \frac{1}{3}\sqrt{2} by the reciprocal of \frac{3\sqrt{2}}{2}.
\frac{\frac{1}{3}\times 2}{3}
Cancel out \sqrt{2} in both numerator and denominator.
\frac{\frac{2}{3}}{3}
Multiply \frac{1}{3} and 2 to get \frac{2}{3}.
\frac{2}{3\times 3}
Express \frac{\frac{2}{3}}{3} as a single fraction.
\frac{2}{9}
Multiply 3 and 3 to get 9.