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2\sqrt{2}+\left(-1\right)^{3}-2\times \frac{\sqrt{2}}{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
2\sqrt{2}-1-2\times \frac{\sqrt{2}}{2}
Calculate -1 to the power of 3 and get -1.
2\sqrt{2}-1-\sqrt{2}
Cancel out 2 and 2.
\sqrt{2}-1
Combine 2\sqrt{2} and -\sqrt{2} to get \sqrt{2}.