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2\sqrt{2}+\sqrt{3}+5\sqrt{4}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
2\sqrt{2}+\sqrt{3}+5\times 2
Calculate the square root of 4 and get 2.
2\sqrt{2}+\sqrt{3}+10
Multiply 5 and 2 to get 10.