Solve sqrt{8+7x}=x

$$\sqrt { 8 + 7 x } = x$$

Solve for x

$$x=8$$

Solution Steps

Square both sides of the equation.

$$\left(\sqrt{8+7x}\right)^{2}=x^{2}$$

Calculate \sqrt{8+7x} to the power of 2 and get 8+7x.

$$8+7x=x^{2}$$

Subtract x^{2} from both sides.

$$8+7x-x^{2}=0$$

Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.

$$-x^{2}+7x+8=0$$

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx+8. To find a and b, set up a system to be solved.

$$a+b=7 ab=-8=-8$$

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -8.

$$-1,8 -2,4$$

Calculate the sum for each pair.

$$-1+8=7 -2+4=2$$

The solution is the pair that gives sum 7.

$$a=8 b=-1$$

Rewrite -x^{2}+7x+8 as \left(-x^{2}+8x\right)+\left(-x+8\right).

$$\left(-x^{2}+8x\right)+\left(-x+8\right)$$

Factor out -x in the first and -1 in the second group.

$$-x\left(x-8\right)-\left(x-8\right)$$

Factor out common term x-8 by using distributive property.

$$\left(x-8\right)\left(-x-1\right)$$

To find equation solutions, solve x-8=0 and -x-1=0.

$$x=8 x=-1$$

Substitute 8 for x in the equation \sqrt{8+7x}=x.

$$\sqrt{8+7\times 8}=8$$

Simplify. The value x=8 satisfies the equation.

$$8=8$$

Substitute -1 for x in the equation \sqrt{8+7x}=x.

$$\sqrt{8+7\left(-1\right)}=-1$$

Simplify. The value x=-1 does not satisfy the equation because the left and the right hand side have opposite signs.

$$1=-1$$

Equation \sqrt{7x+8}=x has a unique solution.

$$x=8$$