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\sqrt{9}\geq 1-\sqrt{2\times 8}
Add 8 and 1 to get 9.
3\geq 1-\sqrt{2\times 8}
Calculate the square root of 9 and get 3.
3\geq 1-\sqrt{16}
Multiply 2 and 8 to get 16.
3\geq 1-4
Calculate the square root of 16 and get 4.
3\geq -3
Subtract 4 from 1 to get -3.
\text{true}
Compare 3 and -3.