Solve sqrt{7x+51}+14=18

$$\sqrt { 7 x + 51 } + 14 = 18$$

Solve for x

$$x=-5$$

Steps for Solving Radical Equations

Subtract 14 from both sides of the equation.

$$\sqrt{7x+51}+14-14=18-14$$

Subtracting 14 from itself leaves 0.

$$\sqrt{7x+51}=18-14$$

Subtract 14 from 18.

$$\sqrt{7x+51}=4$$

Square both sides of the equation.

$$7x+51=16$$

Subtract 51 from both sides of the equation.

$$7x+51-51=16-51$$

Subtracting 51 from itself leaves 0.

$$7x=16-51$$

Subtract 51 from 16.

$$7x=-35$$

Divide both sides by 7.

$$\frac{7x}{7}=-\frac{35}{7}$$

Dividing by 7 undoes the multiplication by 7.

$$x=-\frac{35}{7}$$

Divide -35 by 7.

$$x=-5$$