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\sqrt{7x+2}=6-x
Subtract x from both sides of the equation.
\left(\sqrt{7x+2}\right)^{2}=\left(6-x\right)^{2}
Square both sides of the equation.
7x+2=\left(6-x\right)^{2}
Calculate \sqrt{7x+2} to the power of 2 and get 7x+2.
7x+2=36-12x+x^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(6-x\right)^{2}.
7x+2-36=-12x+x^{2}
Subtract 36 from both sides.
7x-34=-12x+x^{2}
Subtract 36 from 2 to get -34.
7x-34+12x=x^{2}
Add 12x to both sides.
19x-34=x^{2}
Combine 7x and 12x to get 19x.
19x-34-x^{2}=0
Subtract x^{2} from both sides.
-x^{2}+19x-34=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=19 ab=-\left(-34\right)=34
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx-34. To find a and b, set up a system to be solved.
1,34 2,17
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 34.
1+34=35 2+17=19
Calculate the sum for each pair.
a=17 b=2
The solution is the pair that gives sum 19.
\left(-x^{2}+17x\right)+\left(2x-34\right)
Rewrite -x^{2}+19x-34 as \left(-x^{2}+17x\right)+\left(2x-34\right).
-x\left(x-17\right)+2\left(x-17\right)
Factor out -x in the first and 2 in the second group.
\left(x-17\right)\left(-x+2\right)
Factor out common term x-17 by using distributive property.
x=17 x=2
To find equation solutions, solve x-17=0 and -x+2=0.
\sqrt{7\times 17+2}+17=6
Substitute 17 for x in the equation \sqrt{7x+2}+x=6.
28=6
Simplify. The value x=17 does not satisfy the equation.
\sqrt{7\times 2+2}+2=6
Substitute 2 for x in the equation \sqrt{7x+2}+x=6.
6=6
Simplify. The value x=2 satisfies the equation.
x=2
Equation \sqrt{7x+2}=6-x has a unique solution.