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x\sqrt{7}+\sqrt{5}=x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
x\sqrt{7}+\sqrt{5}-x=0
Subtract x from both sides.
x\sqrt{7}-x=-\sqrt{5}
Subtract \sqrt{5} from both sides. Anything subtracted from zero gives its negation.
\left(\sqrt{7}-1\right)x=-\sqrt{5}
Combine all terms containing x.
\frac{\left(\sqrt{7}-1\right)x}{\sqrt{7}-1}=-\frac{\sqrt{5}}{\sqrt{7}-1}
Divide both sides by \sqrt{7}-1.
x=-\frac{\sqrt{5}}{\sqrt{7}-1}
Dividing by \sqrt{7}-1 undoes the multiplication by \sqrt{7}-1.
x=-\frac{\sqrt{5}\left(\sqrt{7}+1\right)}{6}
Divide -\sqrt{5} by \sqrt{7}-1.