Solve sqrt{7*3+2*5-(43-8-3^2)+2^4}

$$\sqrt { 7 \times 3 + 2 \times 5 - ( 43 - 8 - 3 ^ { 2 } ) + 2 ^ { 4 } }$$

Evaluate

$$\sqrt{21}\approx 4.582575695$$

Solution Steps

Multiply 7 and 3 to get 21. Multiply 2 and 5 to get 10.

$$\sqrt{21+10-\left(43-8-3^{2}\right)+2^{4}}$$

Add 21 and 10 to get 31.

$$\sqrt{31-\left(43-8-3^{2}\right)+2^{4}}$$

Subtract 8 from 43 to get 35.

$$\sqrt{31-\left(35-3^{2}\right)+2^{4}}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{31-\left(35-9\right)+2^{4}}$$

Subtract 9 from 35 to get 26.

$$\sqrt{31-26+2^{4}}$$

Subtract 26 from 31 to get 5.

$$\sqrt{5+2^{4}}$$

Calculate 2 to the power of 4 and get 16.

$$\sqrt{5+16}$$

Add 5 and 16 to get 21.

$$\sqrt{21}$$