Solve sqrt{6}-(x+sqrt{3})=sqrt{3}

$$\sqrt { 6 } - ( x + \sqrt { 3 } ) = \sqrt { 3 }$$

Solve for x

$$x=\sqrt{6}-2\sqrt{3}\approx -1.014611872$$

Steps for Solving Linear Equation

To find the opposite of x+\sqrt{3}, find the opposite of each term.

$$\sqrt{6}-x-\sqrt{3}=\sqrt{3}$$

Subtract \sqrt{6} from both sides.

$$-x-\sqrt{3}=\sqrt{3}-\sqrt{6}$$

Add \sqrt{3} to both sides.

$$-x=\sqrt{3}-\sqrt{6}+\sqrt{3}$$

Combine \sqrt{3} and \sqrt{3} to get 2\sqrt{3}.

$$-x=2\sqrt{3}-\sqrt{6}$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{2\sqrt{3}-\sqrt{6}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{2\sqrt{3}-\sqrt{6}}{-1}$$

Divide 2\sqrt{3}-\sqrt{6} by -1.

$$x=\sqrt{6}-2\sqrt{3}$$