Solve sqrt{6^2-5^2+2^3+2^2+sqrt[3]{8}}=

$$\sqrt { 6 ^ { 2 } - 5 ^ { 2 } + 2 ^ { 3 } + 2 ^ { 2 } + \sqrt[ 3 ] { 8 } } =$$

Evaluate

$$5$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\sqrt{36-5^{2}+2^{3}+2^{2}+\sqrt[3]{8}}$$

Calculate 5 to the power of 2 and get 25.

$$\sqrt{36-25+2^{3}+2^{2}+\sqrt[3]{8}}$$

Subtract 25 from 36 to get 11.

$$\sqrt{11+2^{3}+2^{2}+\sqrt[3]{8}}$$

Calculate 2 to the power of 3 and get 8.

$$\sqrt{11+8+2^{2}+\sqrt[3]{8}}$$

Add 11 and 8 to get 19.

$$\sqrt{19+2^{2}+\sqrt[3]{8}}$$

Calculate 2 to the power of 2 and get 4.

$$\sqrt{19+4+\sqrt[3]{8}}$$

Add 19 and 4 to get 23.

$$\sqrt{23+\sqrt[3]{8}}$$

Calculate \sqrt[3]{8} and get 2.

$$\sqrt{23+2}$$

Add 23 and 2 to get 25.

$$\sqrt{25}$$

Calculate the square root of 25 and get 5.

$$5$$

Factor

$$5$$