Solve for b
b=6
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3\sqrt{6}=3\sqrt{b}
Factor 54=3^{2}\times 6. Rewrite the square root of the product \sqrt{3^{2}\times 6} as the product of square roots \sqrt{3^{2}}\sqrt{6}. Take the square root of 3^{2}.
3\sqrt{b}=3\sqrt{6}
Swap sides so that all variable terms are on the left hand side.
\sqrt{b}=\sqrt{6}
Cancel out 3 on both sides.
b=6
Square both sides of the equation.
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