Solve for x
x=0
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\left(\sqrt{5x+9}\right)^{2}=\left(2x+3\right)^{2}
Square both sides of the equation.
5x+9=\left(2x+3\right)^{2}
Calculate \sqrt{5x+9} to the power of 2 and get 5x+9.
5x+9=4x^{2}+12x+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+3\right)^{2}.
5x+9-4x^{2}=12x+9
Subtract 4x^{2} from both sides.
5x+9-4x^{2}-12x=9
Subtract 12x from both sides.
-7x+9-4x^{2}=9
Combine 5x and -12x to get -7x.
-7x+9-4x^{2}-9=0
Subtract 9 from both sides.
-7x-4x^{2}=0
Subtract 9 from 9 to get 0.
x\left(-7-4x\right)=0
Factor out x.
x=0 x=-\frac{7}{4}
To find equation solutions, solve x=0 and -7-4x=0.
\sqrt{5\times 0+9}=2\times 0+3
Substitute 0 for x in the equation \sqrt{5x+9}=2x+3.
3=3
Simplify. The value x=0 satisfies the equation.
\sqrt{5\left(-\frac{7}{4}\right)+9}=2\left(-\frac{7}{4}\right)+3
Substitute -\frac{7}{4} for x in the equation \sqrt{5x+9}=2x+3.
\frac{1}{2}=-\frac{1}{2}
Simplify. The value x=-\frac{7}{4} does not satisfy the equation because the left and the right hand side have opposite signs.
x=0
Equation \sqrt{5x+9}=2x+3 has a unique solution.
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