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\sqrt{5x+4}=2x+1
Subtract -1 from both sides of the equation.
\left(\sqrt{5x+4}\right)^{2}=\left(2x+1\right)^{2}
Square both sides of the equation.
5x+4=\left(2x+1\right)^{2}
Calculate \sqrt{5x+4} to the power of 2 and get 5x+4.
5x+4=4x^{2}+4x+1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+1\right)^{2}.
5x+4-4x^{2}=4x+1
Subtract 4x^{2} from both sides.
5x+4-4x^{2}-4x=1
Subtract 4x from both sides.
x+4-4x^{2}=1
Combine 5x and -4x to get x.
x+4-4x^{2}-1=0
Subtract 1 from both sides.
x+3-4x^{2}=0
Subtract 1 from 4 to get 3.
-4x^{2}+x+3=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=1 ab=-4\times 3=-12
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -4x^{2}+ax+bx+3. To find a and b, set up a system to be solved.
-1,12 -2,6 -3,4
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -12.
-1+12=11 -2+6=4 -3+4=1
Calculate the sum for each pair.
a=4 b=-3
The solution is the pair that gives sum 1.
\left(-4x^{2}+4x\right)+\left(-3x+3\right)
Rewrite -4x^{2}+x+3 as \left(-4x^{2}+4x\right)+\left(-3x+3\right).
4x\left(-x+1\right)+3\left(-x+1\right)
Factor out 4x in the first and 3 in the second group.
\left(-x+1\right)\left(4x+3\right)
Factor out common term -x+1 by using distributive property.
x=1 x=-\frac{3}{4}
To find equation solutions, solve -x+1=0 and 4x+3=0.
\sqrt{5\times 1+4}-1=2\times 1
Substitute 1 for x in the equation \sqrt{5x+4}-1=2x.
2=2
Simplify. The value x=1 satisfies the equation.
\sqrt{5\left(-\frac{3}{4}\right)+4}-1=2\left(-\frac{3}{4}\right)
Substitute -\frac{3}{4} for x in the equation \sqrt{5x+4}-1=2x.
-\frac{1}{2}=-\frac{3}{2}
Simplify. The value x=-\frac{3}{4} does not satisfy the equation.
x=1
Equation \sqrt{5x+4}=2x+1 has a unique solution.