Solve sqrt{5^2-3^2+3(4)-(14div2)^2}

$$\sqrt { 5 ^ { 2 } - 3 ^ { 2 } + 3 ( 4 ) - ( 14 \div 2 ) ^ { 2 } }$$

Evaluate

$$\text{Indeterminate}$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\sqrt{25-3^{2}+3\times 4-\left(\frac{14}{2}\right)^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{25-9+3\times 4-\left(\frac{14}{2}\right)^{2}}$$

Subtract 9 from 25 to get 16.

$$\sqrt{16+3\times 4-\left(\frac{14}{2}\right)^{2}}$$

Multiply 3 and 4 to get 12.

$$\sqrt{16+12-\left(\frac{14}{2}\right)^{2}}$$

Add 16 and 12 to get 28.

$$\sqrt{28-\left(\frac{14}{2}\right)^{2}}$$

Divide 14 by 2 to get 7.

$$\sqrt{28-7^{2}}$$

Calculate 7 to the power of 2 and get 49.

$$\sqrt{28-49}$$

Subtract 49 from 28 to get -21.

$$\sqrt{-21}$$