Solve sqrt{5^2}+5^0:1^6+sqrt{25}9-3^3

$$\sqrt { 5 ^ { 2 } } + 5 ^ { 0 } : 1 ^ { 6 } + \sqrt { 25 } 9 - 3 ^ { 3 }$$

Evaluate

$$24$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\sqrt{25}+\frac{5^{0}}{1^{6}}+9\sqrt{25}-3^{3}$$

Calculate the square root of 25 and get 5.

$$5+\frac{5^{0}}{1^{6}}+9\sqrt{25}-3^{3}$$

Calculate 5 to the power of 0 and get 1.

$$5+\frac{1}{1^{6}}+9\sqrt{25}-3^{3}$$

Calculate 1 to the power of 6 and get 1.

$$5+\frac{1}{1}+9\sqrt{25}-3^{3}$$

Anything divided by one gives itself.

$$5+1+9\sqrt{25}-3^{3}$$

Add 5 and 1 to get 6.

$$6+9\sqrt{25}-3^{3}$$

Calculate the square root of 25 and get 5.

$$6+9\times 5-3^{3}$$

Multiply 9 and 5 to get 45.

$$6+45-3^{3}$$

Add 6 and 45 to get 51.

$$51-3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$51-27$$

Subtract 27 from 51 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$