Solve sqrt{5^2}+5^0:1^6+sqrt{25}.9-3^3

$$\sqrt { 5 ^ { 2 } } + 5 ^ { 0 } : 1 ^ { 6 } + \sqrt { 25 } .9 - 3 ^ { 3 }$$

Evaluate

$$-16.5$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\sqrt{25}+\frac{5^{0}}{1^{6}}+0.9\sqrt{25}-3^{3}$$

Calculate the square root of 25 and get 5.

$$5+\frac{5^{0}}{1^{6}}+0.9\sqrt{25}-3^{3}$$

Calculate 5 to the power of 0 and get 1.

$$5+\frac{1}{1^{6}}+0.9\sqrt{25}-3^{3}$$

Calculate 1 to the power of 6 and get 1.

$$5+\frac{1}{1}+0.9\sqrt{25}-3^{3}$$

Anything divided by one gives itself.

$$5+1+0.9\sqrt{25}-3^{3}$$

Add 5 and 1 to get 6.

$$6+0.9\sqrt{25}-3^{3}$$

Calculate the square root of 25 and get 5.

$$6+0.9\times 5-3^{3}$$

Multiply 0.9 and 5 to get 4.5.

$$6+4.5-3^{3}$$

Add 6 and 4.5 to get 10.5.

$$10.5-3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$10.5-27$$

Subtract 27 from 10.5 to get -16.5.

$$-16.5$$

Factor

$$-16.5$$