Solve sqrt{5^{2}+3^2+4^2+4^2+2^2}

$$\sqrt { 5 ^ { 2 } + 3 ^ { 2 } + 4 ^ { 2 } + 4 ^ { 2 } + 2 ^ { 2 } }$$

Evaluate

$$\sqrt{70}\approx 8.366600265$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$\sqrt{25+3^{2}+4^{2}+4^{2}+2^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{25+9+4^{2}+4^{2}+2^{2}}$$

Add 25 and 9 to get 34.

$$\sqrt{34+4^{2}+4^{2}+2^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\sqrt{34+16+4^{2}+2^{2}}$$

Add 34 and 16 to get 50.

$$\sqrt{50+4^{2}+2^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\sqrt{50+16+2^{2}}$$

Add 50 and 16 to get 66.

$$\sqrt{66+2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\sqrt{66+4}$$

Add 66 and 4 to get 70.

$$\sqrt{70}$$