Solve sqrt{49}-3^3+0^7-2^2*(-3)

$$\sqrt { 49 } - 3 ^ { 3 } + 0 ^ { 7 } - 2 ^ { 2 } \cdot ( - 3 )$$

Evaluate

$$-8$$

Solution Steps

Calculate the square root of 49 and get 7.

$$7-3^{3}+0^{7}-2^{2}\left(-3\right)$$

Calculate 3 to the power of 3 and get 27.

$$7-27+0^{7}-2^{2}\left(-3\right)$$

Subtract 27 from 7 to get -20.

$$-20+0^{7}-2^{2}\left(-3\right)$$

Calculate 0 to the power of 7 and get 0.

$$-20+0-2^{2}\left(-3\right)$$

Add -20 and 0 to get -20.

$$-20-2^{2}\left(-3\right)$$

Calculate 2 to the power of 2 and get 4.

$$-20-4\left(-3\right)$$

Multiply 4 and -3 to get -12.

$$-20-\left(-12\right)$$

The opposite of -12 is 12.

$$-20+12$$

Add -20 and 12 to get -8.

$$-8$$

Factor

$$-8$$