Solve sqrt{49}-(4^3-3-11+70:(3+4)*5^0+101)

$$\sqrt { 49 } - ( 4 ^ { 3 } - 3 - 11 + 70 : ( 3 + 4 ) \cdot 5 ^ { 0 } + 101 )$$

Evaluate

$$-154$$

Solution Steps

Calculate the square root of 49 and get 7.

$$7-\left(4^{3}-3-11+\frac{70}{3+4}\times 5^{0}+101\right)$$

Calculate 4 to the power of 3 and get 64.

$$7-\left(64-3-11+\frac{70}{3+4}\times 5^{0}+101\right)$$

Subtract 3 from 64 to get 61.

$$7-\left(61-11+\frac{70}{3+4}\times 5^{0}+101\right)$$

Subtract 11 from 61 to get 50.

$$7-\left(50+\frac{70}{3+4}\times 5^{0}+101\right)$$

Add 3 and 4 to get 7.

$$7-\left(50+\frac{70}{7}\times 5^{0}+101\right)$$

Divide 70 by 7 to get 10.

$$7-\left(50+10\times 5^{0}+101\right)$$

Calculate 5 to the power of 0 and get 1.

$$7-\left(50+10\times 1+101\right)$$

Multiply 10 and 1 to get 10.

$$7-\left(50+10+101\right)$$

Add 50 and 10 to get 60.

$$7-\left(60+101\right)$$

Add 60 and 101 to get 161.

$$7-161$$

Subtract 161 from 7 to get -154.

$$-154$$

Factor

$$-154$$