Solve sqrt{46,7^2+54*65^2}

$$\sqrt { 46,7 ^ { 2 } + 54 \cdot 65 ^ { 2 } }$$

Evaluate

$$2\sqrt{57601}\approx 480.004166649$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$\sqrt{46\times 49+54\times 65^{2}}$$

Multiply 46 and 49 to get 2254.

$$\sqrt{2254+54\times 65^{2}}$$

Calculate 65 to the power of 2 and get 4225.

$$\sqrt{2254+54\times 4225}$$

Multiply 54 and 4225 to get 228150.

$$\sqrt{2254+228150}$$

Add 2254 and 228150 to get 230404.

$$\sqrt{230404}$$

Factor 230404=2^{2}\times 57601. Rewrite the square root of the product \sqrt{2^{2}\times 57601} as the product of square roots \sqrt{2^{2}}\sqrt{57601}. Take the square root of 2^{2}.

$$2\sqrt{57601}$$