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\left(\sqrt{46-6w}\right)^{2}=\left(w-5\right)^{2}
Square both sides of the equation.
46-6w=\left(w-5\right)^{2}
Calculate \sqrt{46-6w} to the power of 2 and get 46-6w.
46-6w=w^{2}-10w+25
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(w-5\right)^{2}.
46-6w-w^{2}=-10w+25
Subtract w^{2} from both sides.
46-6w-w^{2}+10w=25
Add 10w to both sides.
46+4w-w^{2}=25
Combine -6w and 10w to get 4w.
46+4w-w^{2}-25=0
Subtract 25 from both sides.
21+4w-w^{2}=0
Subtract 25 from 46 to get 21.
-w^{2}+4w+21=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=4 ab=-21=-21
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -w^{2}+aw+bw+21. To find a and b, set up a system to be solved.
-1,21 -3,7
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -21.
-1+21=20 -3+7=4
Calculate the sum for each pair.
a=7 b=-3
The solution is the pair that gives sum 4.
\left(-w^{2}+7w\right)+\left(-3w+21\right)
Rewrite -w^{2}+4w+21 as \left(-w^{2}+7w\right)+\left(-3w+21\right).
-w\left(w-7\right)-3\left(w-7\right)
Factor out -w in the first and -3 in the second group.
\left(w-7\right)\left(-w-3\right)
Factor out common term w-7 by using distributive property.
w=7 w=-3
To find equation solutions, solve w-7=0 and -w-3=0.
\sqrt{46-6\times 7}=7-5
Substitute 7 for w in the equation \sqrt{46-6w}=w-5.
2=2
Simplify. The value w=7 satisfies the equation.
\sqrt{46-6\left(-3\right)}=-3-5
Substitute -3 for w in the equation \sqrt{46-6w}=w-5.
8=-8
Simplify. The value w=-3 does not satisfy the equation because the left and the right hand side have opposite signs.
w=7
Equation \sqrt{46-6w}=w-5 has a unique solution.