Solve sqrt{4x-8}+5=11

$$\sqrt { 4 x - 8 } + 5 = 11$$

Solve for x

$$x=11$$

Steps for Solving Radical Equations

Subtract 5 from both sides of the equation.

$$\sqrt{4x-8}+5-5=11-5$$

Subtracting 5 from itself leaves 0.

$$\sqrt{4x-8}=11-5$$

Subtract 5 from 11.

$$\sqrt{4x-8}=6$$

Square both sides of the equation.

$$4x-8=36$$

Add 8 to both sides of the equation.

$$4x-8-\left(-8\right)=36-\left(-8\right)$$

Subtracting -8 from itself leaves 0.

$$4x=36-\left(-8\right)$$

Subtract -8 from 36.

$$4x=44$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{44}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{44}{4}$$

Divide 44 by 4.

$$x=11$$