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\sqrt{4x}=-\left(-x+3\right)
Subtract -x+3 from both sides of the equation.
\sqrt{4x}=-\left(-x\right)-3
To find the opposite of -x+3, find the opposite of each term.
\sqrt{4x}=x-3
The opposite of -x is x.
\left(\sqrt{4x}\right)^{2}=\left(x-3\right)^{2}
Square both sides of the equation.
4x=\left(x-3\right)^{2}
Calculate \sqrt{4x} to the power of 2 and get 4x.
4x=x^{2}-6x+9
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
4x-x^{2}=-6x+9
Subtract x^{2} from both sides.
4x-x^{2}+6x=9
Add 6x to both sides.
10x-x^{2}=9
Combine 4x and 6x to get 10x.
10x-x^{2}-9=0
Subtract 9 from both sides.
-x^{2}+10x-9=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=10 ab=-\left(-9\right)=9
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx-9. To find a and b, set up a system to be solved.
1,9 3,3
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 9.
1+9=10 3+3=6
Calculate the sum for each pair.
a=9 b=1
The solution is the pair that gives sum 10.
\left(-x^{2}+9x\right)+\left(x-9\right)
Rewrite -x^{2}+10x-9 as \left(-x^{2}+9x\right)+\left(x-9\right).
-x\left(x-9\right)+x-9
Factor out -x in -x^{2}+9x.
\left(x-9\right)\left(-x+1\right)
Factor out common term x-9 by using distributive property.
x=9 x=1
To find equation solutions, solve x-9=0 and -x+1=0.
\sqrt{4\times 9}-9+3=0
Substitute 9 for x in the equation \sqrt{4x}-x+3=0.
0=0
Simplify. The value x=9 satisfies the equation.
\sqrt{4\times 1}-1+3=0
Substitute 1 for x in the equation \sqrt{4x}-x+3=0.
4=0
Simplify. The value x=1 does not satisfy the equation.
x=9
Equation \sqrt{4x}=x-3 has a unique solution.