Solve sqrt{4x+6}+8=10

$$\sqrt { 4 x + 6 } + 8 = 10$$

Solve for x

$$x=-\frac{1}{2}=-0.5$$

Steps for Solving Radical Equations

Subtract 8 from both sides of the equation.

$$\sqrt{4x+6}+8-8=10-8$$

Subtracting 8 from itself leaves 0.

$$\sqrt{4x+6}=10-8$$

Subtract 8 from 10.

$$\sqrt{4x+6}=2$$

Square both sides of the equation.

$$4x+6=4$$

Subtract 6 from both sides of the equation.

$$4x+6-6=4-6$$

Subtracting 6 from itself leaves 0.

$$4x=4-6$$

Subtract 6 from 4.

$$4x=-2$$

Divide both sides by 4.

$$\frac{4x}{4}=-\frac{2}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=-\frac{2}{4}$$

Reduce the fraction \frac{-2}{4} to lowest terms by extracting and canceling out 2.

$$x=-\frac{1}{2}$$