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\left(\sqrt{4-9x}\right)^{2}=\left(3x\right)^{2}
Square both sides of the equation.
4-9x=\left(3x\right)^{2}
Calculate \sqrt{4-9x} to the power of 2 and get 4-9x.
4-9x=3^{2}x^{2}
Expand \left(3x\right)^{2}.
4-9x=9x^{2}
Calculate 3 to the power of 2 and get 9.
4-9x-9x^{2}=0
Subtract 9x^{2} from both sides.
-9x^{2}-9x+4=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=-9 ab=-9\times 4=-36
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -9x^{2}+ax+bx+4. To find a and b, set up a system to be solved.
1,-36 2,-18 3,-12 4,-9 6,-6
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -36.
1-36=-35 2-18=-16 3-12=-9 4-9=-5 6-6=0
Calculate the sum for each pair.
a=3 b=-12
The solution is the pair that gives sum -9.
\left(-9x^{2}+3x\right)+\left(-12x+4\right)
Rewrite -9x^{2}-9x+4 as \left(-9x^{2}+3x\right)+\left(-12x+4\right).
3x\left(-3x+1\right)+4\left(-3x+1\right)
Factor out 3x in the first and 4 in the second group.
\left(-3x+1\right)\left(3x+4\right)
Factor out common term -3x+1 by using distributive property.
x=\frac{1}{3} x=-\frac{4}{3}
To find equation solutions, solve -3x+1=0 and 3x+4=0.
\sqrt{4-9\times \frac{1}{3}}=3\times \frac{1}{3}
Substitute \frac{1}{3} for x in the equation \sqrt{4-9x}=3x.
1=1
Simplify. The value x=\frac{1}{3} satisfies the equation.
\sqrt{4-9\left(-\frac{4}{3}\right)}=3\left(-\frac{4}{3}\right)
Substitute -\frac{4}{3} for x in the equation \sqrt{4-9x}=3x.
4=-4
Simplify. The value x=-\frac{4}{3} does not satisfy the equation because the left and the right hand side have opposite signs.
x=\frac{1}{3}
Equation \sqrt{4-9x}=3x has a unique solution.