Solve sqrt{4}+6-7/11+7-5=

$$\sqrt { 4 } + 6 - \frac { 7 } { 11 } + 7 - 5 =$$

Evaluate

$$\frac{103}{11}\approx 9.363636364$$

Solution Steps

Calculate the square root of 4 and get 2.

$$2+6-\frac{7}{11}+7-5$$

Add 2 and 6 to get 8.

$$8-\frac{7}{11}+7-5$$

Convert 8 to fraction \frac{88}{11}.

$$\frac{88}{11}-\frac{7}{11}+7-5$$

Since \frac{88}{11} and \frac{7}{11} have the same denominator, subtract them by subtracting their numerators.

$$\frac{88-7}{11}+7-5$$

Subtract 7 from 88 to get 81.

$$\frac{81}{11}+7-5$$

Convert 7 to fraction \frac{77}{11}.

$$\frac{81}{11}+\frac{77}{11}-5$$

Since \frac{81}{11} and \frac{77}{11} have the same denominator, add them by adding their numerators.

$$\frac{81+77}{11}-5$$

Add 81 and 77 to get 158.

$$\frac{158}{11}-5$$

Convert 5 to fraction \frac{55}{11}.

$$\frac{158}{11}-\frac{55}{11}$$

Since \frac{158}{11} and \frac{55}{11} have the same denominator, subtract them by subtracting their numerators.

$$\frac{158-55}{11}$$

Subtract 55 from 158 to get 103.

$$\frac{103}{11}$$

Factor

$$\frac{103}{11} = 9\frac{4}{11} = 9.363636363636363$$