Solve sqrt{4*2^2}=4*2^2=16

$$\sqrt { 4 \times 2 ^ { 2 } } = 4 \times 2 ^ { 2 } = 16$$

Verify

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{4\times 4}=4\times 2^{2}\text{ and }4\times 2^{2}=16$$

Multiply 4 and 4 to get 16.

$$\sqrt{16}=4\times 2^{2}\text{ and }4\times 2^{2}=16$$

Calculate the square root of 16 and get 4.

$$4=4\times 2^{2}\text{ and }4\times 2^{2}=16$$

Calculate 2 to the power of 2 and get 4.

$$4=4\times 4\text{ and }4\times 2^{2}=16$$

Multiply 4 and 4 to get 16.

$$4=16\text{ and }4\times 2^{2}=16$$

Compare 4 and 16.

$$\text{false}\text{ and }4\times 2^{2}=16$$

Calculate 2 to the power of 2 and get 4.

$$\text{false}\text{ and }4\times 4=16$$

Multiply 4 and 4 to get 16.

$$\text{false}\text{ and }16=16$$

Compare 16 and 16.

$$\text{false}\text{ and }\text{true}$$

The conjunction of \text{false} and \text{true} is \text{false}.

$$\text{false}$$