Solve sqrt{4+105:5}-sqrt[3]{64}:(3+1)+(3*2-3)^0=

$$\sqrt { 4 + 105 : 5 } - \sqrt[ 3 ] { 64 } : ( 3 + 1 ) + ( 3 \cdot 2 - 3 ) ^ { 0 } =$$

Evaluate

$$5$$

Solution Steps

Divide 105 by 5 to get 21.

$$\sqrt{4+21}-\frac{\sqrt[3]{64}}{3+1}+\left(3\times 2-3\right)^{0}$$

Add 4 and 21 to get 25.

$$\sqrt{25}-\frac{\sqrt[3]{64}}{3+1}+\left(3\times 2-3\right)^{0}$$

Calculate the square root of 25 and get 5.

$$5-\frac{\sqrt[3]{64}}{3+1}+\left(3\times 2-3\right)^{0}$$

Calculate \sqrt[3]{64} and get 4.

$$5-\frac{4}{3+1}+\left(3\times 2-3\right)^{0}$$

Add 3 and 1 to get 4.

$$5-\frac{4}{4}+\left(3\times 2-3\right)^{0}$$

Divide 4 by 4 to get 1.

$$5-1+\left(3\times 2-3\right)^{0}$$

Subtract 1 from 5 to get 4.

$$4+\left(3\times 2-3\right)^{0}$$

Multiply 3 and 2 to get 6.

$$4+\left(6-3\right)^{0}$$

Subtract 3 from 6 to get 3.

$$4+3^{0}$$

Calculate 3 to the power of 0 and get 1.

$$4+1$$

Add 4 and 1 to get 5.

$$5$$

Factor

$$5$$