Solve sqrt{36}-sqrt{81}-1/10+5^2=

$$\sqrt { 36 } - \sqrt { 81 } - \frac { 1 } { 10 } + 5 ^ { 2 } =$$

Evaluate

$$\frac{219}{10}=21.9$$

Solution Steps

Calculate the square root of 36 and get 6.

$$6-\sqrt{81}-\frac{1}{10}+5^{2}$$

Calculate the square root of 81 and get 9.

$$6-9-\frac{1}{10}+5^{2}$$

Subtract 9 from 6 to get -3.

$$-3-\frac{1}{10}+5^{2}$$

Convert -3 to fraction -\frac{30}{10}.

$$-\frac{30}{10}-\frac{1}{10}+5^{2}$$

Since -\frac{30}{10} and \frac{1}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-30-1}{10}+5^{2}$$

Subtract 1 from -30 to get -31.

$$-\frac{31}{10}+5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$-\frac{31}{10}+25$$

Convert 25 to fraction \frac{250}{10}.

$$-\frac{31}{10}+\frac{250}{10}$$

Since -\frac{31}{10} and \frac{250}{10} have the same denominator, add them by adding their numerators.

$$\frac{-31+250}{10}$$

Add -31 and 250 to get 219.

$$\frac{219}{10}$$

Factor

$$\frac{3 \cdot 73}{2 \cdot 5} = 21\frac{9}{10} = 21.9$$