Solve sqrt{36}*sqrt{1/9}-sqrt{(-2)^2}

$$\sqrt { 36 } \times \sqrt { \frac { 1 } { 9 } } - \sqrt { ( - 2 ) ^ { 2 } }$$

Evaluate

$$0$$

Solution Steps

Calculate the square root of 36 and get 6.

$$6\sqrt{\frac{1}{9}}-\sqrt{\left(-2\right)^{2}}$$

Rewrite the square root of the division \frac{1}{9} as the division of square roots \frac{\sqrt{1}}{\sqrt{9}}. Take the square root of both numerator and denominator.

$$6\times \frac{1}{3}-\sqrt{\left(-2\right)^{2}}$$

Multiply 6 and \frac{1}{3} to get \frac{6}{3}.

$$\frac{6}{3}-\sqrt{\left(-2\right)^{2}}$$

Divide 6 by 3 to get 2.

$$2-\sqrt{\left(-2\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$2-\sqrt{4}$$

Calculate the square root of 4 and get 2.

$$2-2$$

Subtract 2 from 2 to get 0.

$$0$$

Factor

$$0$$