Solve sqrt{36}*(-6)+2^5:(-2)-(-2)+15^2=

$$\sqrt { 36 } \cdot ( - 6 ) + 2 ^ { 5 } : ( - 2 ) - ( - 2 ) + 15 ^ { 2 } =$$

Evaluate

$$175$$

Solution Steps

Calculate the square root of 36 and get 6.

$$6\left(-6\right)+\frac{2^{5}}{-2}-\left(-2\right)+15^{2}$$

Multiply 6 and -6 to get -36.

$$-36+\frac{2^{5}}{-2}-\left(-2\right)+15^{2}$$

Calculate 2 to the power of 5 and get 32.

$$-36+\frac{32}{-2}-\left(-2\right)+15^{2}$$

Divide 32 by -2 to get -16.

$$-36-16-\left(-2\right)+15^{2}$$

Subtract 16 from -36 to get -52.

$$-52-\left(-2\right)+15^{2}$$

The opposite of -2 is 2.

$$-52+2+15^{2}$$

Add -52 and 2 to get -50.

$$-50+15^{2}$$

Calculate 15 to the power of 2 and get 225.

$$-50+225$$

Add -50 and 225 to get 175.

$$175$$

Factor

$$5^{2}\times 7$$