Solve sqrt{36}=sqrt{6*6}=sqrt{6^2}

$$\sqrt { 36 } = \sqrt { 6 \cdot 6 } = \sqrt { 6 ^ { 2 } }$$

Verify

Solution Steps

Calculate the square root of 36 and get 6.

$$6=\sqrt{6\times 6}\text{ and }\sqrt{6\times 6}=\sqrt{6^{2}}$$

Multiply 6 and 6 to get 36.

$$6=\sqrt{36}\text{ and }\sqrt{6\times 6}=\sqrt{6^{2}}$$

Calculate the square root of 36 and get 6.

$$6=6\text{ and }\sqrt{6\times 6}=\sqrt{6^{2}}$$

Compare 6 and 6.

$$\text{true}\text{ and }\sqrt{6\times 6}=\sqrt{6^{2}}$$

Multiply 6 and 6 to get 36.

$$\text{true}\text{ and }\sqrt{36}=\sqrt{6^{2}}$$

Calculate the square root of 36 and get 6.

$$\text{true}\text{ and }6=\sqrt{6^{2}}$$

Calculate 6 to the power of 2 and get 36.

$$\text{true}\text{ and }6=\sqrt{36}$$

Calculate the square root of 36 and get 6.

$$\text{true}\text{ and }6=6$$

Compare 6 and 6.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$