Solve sqrt{32}-sqrt{8}+1sqrt{36}

$$\sqrt { 32 } - \sqrt { 8 } + 1 \sqrt { 36 }$$

Evaluate

$$2\sqrt{2}+6\approx 8.828427125$$

Solution Steps

Factor 32=4^{2}\times 2. Rewrite the square root of the product \sqrt{4^{2}\times 2} as the product of square roots \sqrt{4^{2}}\sqrt{2}. Take the square root of 4^{2}.

$$4\sqrt{2}-\sqrt{8}+1\sqrt{36}$$

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$4\sqrt{2}-2\sqrt{2}+1\sqrt{36}$$

Combine 4\sqrt{2} and -2\sqrt{2} to get 2\sqrt{2}.

$$2\sqrt{2}+1\sqrt{36}$$

Calculate the square root of 36 and get 6.

$$2\sqrt{2}+1\times 6$$

Multiply 1 and 6 to get 6.

$$2\sqrt{2}+6$$