Solve for y
y=7
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3y-5=16
Square both sides of the equation.
3y-5-\left(-5\right)=16-\left(-5\right)
Add 5 to both sides of the equation.
3y=16-\left(-5\right)
Subtracting -5 from itself leaves 0.
3y=21
Subtract -5 from 16.
\frac{3y}{3}=\frac{21}{3}
Divide both sides by 3.
y=\frac{21}{3}
Dividing by 3 undoes the multiplication by 3.
y=7
Divide 21 by 3.
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