Solve sqrt{3y+4}-6=1

$$\sqrt { 3 y + 4 } - 6 = 1$$

Solve for y

$$y=15$$

Steps for Solving Radical Equations

Add 6 to both sides of the equation.

$$\sqrt{3y+4}-6-\left(-6\right)=1-\left(-6\right)$$

Subtracting -6 from itself leaves 0.

$$\sqrt{3y+4}=1-\left(-6\right)$$

Subtract -6 from 1.

$$\sqrt{3y+4}=7$$

Square both sides of the equation.

$$3y+4=49$$

Subtract 4 from both sides of the equation.

$$3y+4-4=49-4$$

Subtracting 4 from itself leaves 0.

$$3y=49-4$$

Subtract 4 from 49.

$$3y=45$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{45}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{45}{3}$$

Divide 45 by 3.

$$y=15$$