Solve sqrt{3x+40}-17=-12

$$\sqrt { 3 x + 40 } - 17 = - 12$$

Solve for x

$$x=-5$$

Steps for Solving Radical Equations

Add 17 to both sides of the equation.

$$\sqrt{3x+40}-17-\left(-17\right)=-12-\left(-17\right)$$

Subtracting -17 from itself leaves 0.

$$\sqrt{3x+40}=-12-\left(-17\right)$$

Subtract -17 from -12.

$$\sqrt{3x+40}=5$$

Square both sides of the equation.

$$3x+40=25$$

Subtract 40 from both sides of the equation.

$$3x+40-40=25-40$$

Subtracting 40 from itself leaves 0.

$$3x=25-40$$

Subtract 40 from 25.

$$3x=-15$$

Divide both sides by 3.

$$\frac{3x}{3}=-\frac{15}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=-\frac{15}{3}$$

Divide -15 by 3.

$$x=-5$$