Solve sqrt{3x+2}=-16h

$$\sqrt { 3 x + 2 } = - 16 h$$

Solve for x

$$x=\frac{256h^{2}-2}{3}$$

$$h\leq 0$$

Steps for Solving Radical Equations

Square both sides of the equation.

$$3x+2=256h^{2}$$

Subtract 2 from both sides of the equation.

$$3x+2-2=256h^{2}-2$$

Subtracting 2 from itself leaves 0.

$$3x=256h^{2}-2$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{256h^{2}-2}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{256h^{2}-2}{3}$$

Solve for h (complex solution)

$$h=-\frac{\sqrt{3x+2}}{16}$$

Solve for x (complex solution)

$$x=\frac{256h^{2}-2}{3}$$

$$arg(h)\geq \pi \text{ or }h=0$$

Solve for h

$$h=-\frac{\sqrt{3x+2}}{16}$$

$$x\geq -\frac{2}{3}$$