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\sqrt{3x+15}=x+2-3
Subtract 3 from both sides of the equation.
\sqrt{3x+15}=x-1
Subtract 3 from 2 to get -1.
\left(\sqrt{3x+15}\right)^{2}=\left(x-1\right)^{2}
Square both sides of the equation.
3x+15=\left(x-1\right)^{2}
Calculate \sqrt{3x+15} to the power of 2 and get 3x+15.
3x+15=x^{2}-2x+1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
3x+15-x^{2}=-2x+1
Subtract x^{2} from both sides.
3x+15-x^{2}+2x=1
Add 2x to both sides.
5x+15-x^{2}=1
Combine 3x and 2x to get 5x.
5x+15-x^{2}-1=0
Subtract 1 from both sides.
5x+14-x^{2}=0
Subtract 1 from 15 to get 14.
-x^{2}+5x+14=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=5 ab=-14=-14
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx+14. To find a and b, set up a system to be solved.
-1,14 -2,7
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -14.
-1+14=13 -2+7=5
Calculate the sum for each pair.
a=7 b=-2
The solution is the pair that gives sum 5.
\left(-x^{2}+7x\right)+\left(-2x+14\right)
Rewrite -x^{2}+5x+14 as \left(-x^{2}+7x\right)+\left(-2x+14\right).
-x\left(x-7\right)-2\left(x-7\right)
Factor out -x in the first and -2 in the second group.
\left(x-7\right)\left(-x-2\right)
Factor out common term x-7 by using distributive property.
x=7 x=-2
To find equation solutions, solve x-7=0 and -x-2=0.
\sqrt{3\times 7+15}+3=7+2
Substitute 7 for x in the equation \sqrt{3x+15}+3=x+2.
9=9
Simplify. The value x=7 satisfies the equation.
\sqrt{3\left(-2\right)+15}+3=-2+2
Substitute -2 for x in the equation \sqrt{3x+15}+3=x+2.
6=0
Simplify. The value x=-2 does not satisfy the equation.
x=7
Equation \sqrt{3x+15}=x-1 has a unique solution.