Solve sqrt{3}x-sqrt{8}y=0

$$\sqrt { 3 } x - \sqrt { 8 } y = 0$$

Solve for x

$$x=\frac{2\sqrt{6}y}{3}$$

Steps for Solving Linear Equation

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$\sqrt{3}x-2\sqrt{2}y=0$$

Add 2\sqrt{2}y to both sides.

$$\sqrt{3}x=0+2\sqrt{2}y$$

Anything plus zero gives itself.

$$\sqrt{3}x=2\sqrt{2}y$$

Divide both sides by \sqrt{3}.

$$\frac{\sqrt{3}x}{\sqrt{3}}=\frac{2\sqrt{2}y}{\sqrt{3}}$$

Dividing by \sqrt{3} undoes the multiplication by \sqrt{3}.

$$x=\frac{2\sqrt{2}y}{\sqrt{3}}$$

Divide 2y\sqrt{2} by \sqrt{3}.

$$x=\frac{2\sqrt{6}y}{3}$$

Solve for y

$$y=\frac{\sqrt{6}x}{4}$$

Steps for Solving Linear Equation

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$\sqrt{3}x-2\sqrt{2}y=0$$

Subtract \sqrt{3}x from both sides. Anything subtracted from zero gives its negation.

$$-2\sqrt{2}y=-\sqrt{3}x$$

The equation is in standard form.

$$\left(-2\sqrt{2}\right)y=-\sqrt{3}x$$

Divide both sides by -2\sqrt{2}.

$$\frac{\left(-2\sqrt{2}\right)y}{-2\sqrt{2}}=-\frac{\sqrt{3}x}{-2\sqrt{2}}$$

Dividing by -2\sqrt{2} undoes the multiplication by -2\sqrt{2}.

$$y=-\frac{\sqrt{3}x}{-2\sqrt{2}}$$

Divide -\sqrt{3}x by -2\sqrt{2}.

$$y=\frac{\sqrt{6}x}{4}$$