Solve sqrt{3}-frac{sqrt{3}+1}{2}

$$\sqrt { 3 } - \frac { \sqrt { 3 } + 1 } { 2 }$$

Evaluate

$$\frac{\sqrt{3}-1}{2}\approx 0.366025404$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply \sqrt{3} times \frac{2}{2}.

$$\frac{2\sqrt{3}}{2}-\frac{\sqrt{3}+1}{2}$$

Since \frac{2\sqrt{3}}{2} and \frac{\sqrt{3}+1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2\sqrt{3}-\left(\sqrt{3}+1\right)}{2}$$

Do the multiplications in 2\sqrt{3}-\left(\sqrt{3}+1\right).

$$\frac{2\sqrt{3}-\sqrt{3}-1}{2}$$

Do the calculations in 2\sqrt{3}-\sqrt{3}-1.

$$\frac{\sqrt{3}-1}{2}$$

Factor

$$\frac{\sqrt{3} - 1}{2} = 0.3660254037844386$$