Solve sqrt{3}(x+0.2)=28-x

$$\sqrt { 3 } ( x + 0.2 ) = 28 - x$$

Solve for x

$$x = \frac{141 \sqrt{3} - 143}{10} \approx 10.121916387$$

Steps for Solving Linear Equation

Use the distributive property to multiply \sqrt{3} by x+0.2.

$$\sqrt{3}x+0.2\sqrt{3}=28-x$$

Add x to both sides.

$$\sqrt{3}x+0.2\sqrt{3}+x=28$$

Subtract 0.2\sqrt{3} from both sides.

$$\sqrt{3}x+x=28-0.2\sqrt{3}$$

Combine all terms containing x.

$$\left(\sqrt{3}+1\right)x=28-0.2\sqrt{3}$$

The equation is in standard form.

$$\left(\sqrt{3}+1\right)x=-\frac{\sqrt{3}}{5}+28$$

Divide both sides by \sqrt{3}+1.

$$\frac{\left(\sqrt{3}+1\right)x}{\sqrt{3}+1}=\frac{-\frac{\sqrt{3}}{5}+28}{\sqrt{3}+1}$$

Dividing by \sqrt{3}+1 undoes the multiplication by \sqrt{3}+1.

$$x=\frac{-\frac{\sqrt{3}}{5}+28}{\sqrt{3}+1}$$

Divide 28-\frac{\sqrt{3}}{5} by \sqrt{3}+1.

$$x=\frac{141\sqrt{3}-143}{10}$$