Solve sqrt{3^2+4^2+12^2}=?

$$\sqrt { 3 ^ { 2 } + 4 ^ { 2 } + 12 ^ { 2 } } = ?$$

Evaluate

$$13$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\sqrt{9+4^{2}+12^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\sqrt{9+16+12^{2}}$$

Add 9 and 16 to get 25.

$$\sqrt{25+12^{2}}$$

Calculate 12 to the power of 2 and get 144.

$$\sqrt{25+144}$$

Add 25 and 144 to get 169.

$$\sqrt{169}$$

Calculate the square root of 169 and get 13.

$$13$$

Factor

$$13$$