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\sqrt{9+\left(4i\right)^{2}}
Calculate 3 to the power of 2 and get 9.
\sqrt{9-16}
Calculate 4i to the power of 2 and get -16.
\sqrt{-7}
Subtract 16 from 9 to get -7.
\sqrt{7}i
Factor -7=7\left(-1\right). Rewrite the square root of the product \sqrt{7\left(-1\right)} as the product of square roots \sqrt{7}\sqrt{-1}. By definition, the square root of -1 is i.