Solve sqrt{3^0*(3^1+3^2)}

$$\sqrt { 3 ^ { 0 } \times ( 3 ^ { 1 } + 3 ^ { 2 } ) }$$

Evaluate

$$2\sqrt{3}\approx 3.464101615$$

Solution Steps

Calculate 3 to the power of 0 and get 1.

$$\sqrt{1\left(3^{1}+3^{2}\right)}$$

Calculate 3 to the power of 1 and get 3.

$$\sqrt{1\left(3+3^{2}\right)}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{1\left(3+9\right)}$$

Add 3 and 9 to get 12.

$$\sqrt{1\times 12}$$

Multiply 1 and 12 to get 12.

$$\sqrt{12}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$2\sqrt{3}$$