Solve sqrt{29+24-8-(6+3+11)}:(26-23+1)-2=

$$\sqrt { 29 + 24 - 8 - ( 6 + 3 + 11 ) } : ( 26 - 23 + 1 ) - 2 =$$

Evaluate

$$-\frac{3}{4}=-0.75$$

Solution Steps

Add 29 and 24 to get 53.

$$\frac{\sqrt{53-8-\left(6+3+11\right)}}{26-23+1}-2$$

Subtract 8 from 53 to get 45.

$$\frac{\sqrt{45-\left(6+3+11\right)}}{26-23+1}-2$$

Add 6 and 3 to get 9.

$$\frac{\sqrt{45-\left(9+11\right)}}{26-23+1}-2$$

Add 9 and 11 to get 20.

$$\frac{\sqrt{45-20}}{26-23+1}-2$$

Subtract 20 from 45 to get 25.

$$\frac{\sqrt{25}}{26-23+1}-2$$

Calculate the square root of 25 and get 5.

$$\frac{5}{26-23+1}-2$$

Subtract 23 from 26 to get 3.

$$\frac{5}{3+1}-2$$

Add 3 and 1 to get 4.

$$\frac{5}{4}-2$$

Convert 2 to fraction \frac{8}{4}.

$$\frac{5}{4}-\frac{8}{4}$$

Since \frac{5}{4} and \frac{8}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-8}{4}$$

Subtract 8 from 5 to get -3.

$$-\frac{3}{4}$$

Factor

$$-\frac{3}{4} = -0.75$$