Solve sqrt{27}*sqrt{32}+(-1)

$$\sqrt { 27 } \times \sqrt { 32 } + ( - 1 )$$

Evaluate

$$12\sqrt{6}-1\approx 28.393876913$$

Solution Steps

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$3\sqrt{3}\sqrt{32}-1$$

Factor 32=4^{2}\times 2. Rewrite the square root of the product \sqrt{4^{2}\times 2} as the product of square roots \sqrt{4^{2}}\sqrt{2}. Take the square root of 4^{2}.

$$3\sqrt{3}\times 4\sqrt{2}-1$$

Multiply 3 and 4 to get 12.

$$12\sqrt{3}\sqrt{2}-1$$

To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.

$$12\sqrt{6}-1$$