Solve sqrt{25}-sqrt{(-2)^2+sqrt{16}-(-1)}=

$$\sqrt { 25 } - \sqrt { ( - 2 ) ^ { 2 } + \sqrt { 16 } - ( - 1 ) } =$$

Evaluate

$$2$$

Solution Steps

Calculate the square root of 25 and get 5.

$$5-\sqrt{\left(-2\right)^{2}+\sqrt{16}-\left(-1\right)}$$

Calculate -2 to the power of 2 and get 4.

$$5-\sqrt{4+\sqrt{16}-\left(-1\right)}$$

Calculate the square root of 16 and get 4.

$$5-\sqrt{4+4-\left(-1\right)}$$

Add 4 and 4 to get 8.

$$5-\sqrt{8-\left(-1\right)}$$

The opposite of -1 is 1.

$$5-\sqrt{8+1}$$

Add 8 and 1 to get 9.

$$5-\sqrt{9}$$

Calculate the square root of 9 and get 3.

$$5-3$$

Subtract 3 from 5 to get 2.

$$2$$

Factor

$$2$$