Solve sqrt{2x+10}-6=2

$$\sqrt { 2 x + 10 } - 6 = 2$$

Solve for x

$$x=27$$

Steps for Solving Radical Equations

Add 6 to both sides of the equation.

$$\sqrt{2x+10}-6-\left(-6\right)=2-\left(-6\right)$$

Subtracting -6 from itself leaves 0.

$$\sqrt{2x+10}=2-\left(-6\right)$$

Subtract -6 from 2.

$$\sqrt{2x+10}=8$$

Square both sides of the equation.

$$2x+10=64$$

Subtract 10 from both sides of the equation.

$$2x+10-10=64-10$$

Subtracting 10 from itself leaves 0.

$$2x=64-10$$

Subtract 10 from 64.

$$2x=54$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{54}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{54}{2}$$

Divide 54 by 2.

$$x=27$$