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\sqrt{2}\left(-3\right)\sqrt{2}\sqrt{3}\times \frac{1}{2}\sqrt{3}
Factor 6=2\times 3. Rewrite the square root of the product \sqrt{2\times 3} as the product of square roots \sqrt{2}\sqrt{3}.
2\left(-3\right)\sqrt{3}\times \frac{1}{2}\sqrt{3}
Multiply \sqrt{2} and \sqrt{2} to get 2.
2\left(-3\right)\times 3\times \frac{1}{2}
Multiply \sqrt{3} and \sqrt{3} to get 3.
-6\times 3\times \frac{1}{2}
Multiply 2 and -3 to get -6.
-18\times \frac{1}{2}
Multiply -6 and 3 to get -18.
\frac{-18}{2}
Multiply -18 and \frac{1}{2} to get \frac{-18}{2}.
-9
Divide -18 by 2 to get -9.